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1   \section{Results}
2   \label{sec:results}
3  
4 < \noindent {\color{red} In the 11 pb everything is very
5 < simple because there are a few zeros.  This text is written
6 < for the full dataset under the assumption that some of these
7 < numbers will not be zero anymore.}
4 > %\noindent {\color{red} In the 11 pb everything is very
5 > %simple because there are a few zeros.  This text is written
6 > %for the full dataset under the assumption that some of these
7 > %numbers will not be zero anymore.}
8  
9   \begin{figure}[tbh]
10   \begin{center}
# Line 45 | Line 45 | SM MC &2.5 &11.2  & 1.5 & 0.4 & 0.4 \\
45   \end{center}
46   \end{table}
47  
48 < As a cross-check, we can subtract from the yields in
49 < Table~\ref{tab:datayield} the expected DY contributions
50 < from Table~\ref{tab:ABCD-DY} in order to get a ``purer''
51 < estimate of the $t\bar{t}$ contribution.  The result
52 < of this exercise is {\color{red} xx} events.
48 > %As a cross-check, we can subtract from the yields in
49 > %Table~\ref{tab:datayield} the expected DY contributions
50 > %from Table~\ref{tab:ABCD-DY} in order to get a ``purer''
51 > %estimate of the $t\bar{t}$ contribution.  The result
52 > %of this exercise is {\color{red} xx} events.
53  
54   \subsection{Background estimate from the $P_T(\ell\ell)$ method}
55   \label{sec:victoryres}
56  
57  
58 + {\color{red}As mentioned previously, for the 11/pb analysis
59 + we use the $K$ factor from data and take $K_{\rm fudge}=1$.
60 + This will change for the full dataset.  We will also pay
61 + more attention to the statistical errors.}
62  
63   The number of data events in region $D'$, which is defined in
64   Section~\ref{sec:othBG} to be the same as region $D$ but with the
65   $\met/\sqrt{\rm SumJetPt}$ requirement
66   replaced by a $P_T(\ell\ell)/\sqrt{\rm SumJetPt}$ requirement
67 < is $N_{D'}=0$.  Thus the BG prediction is
68 < $N_D = K^{MC} \cdot K_{\rm fudge} \cdot N_{D'} = xx$
69 < where we used $K^{MC}=xx$ and $K_{\rm fudge}=xx \pm yy$.
67 > is $N_{D'}=1$.  Thus the BG prediction is
68 > $N_D = K \cdot K_{\rm fudge} \cdot N_{D'} = 1.5$
69 > where we used $K=1.5 \pm xx$ and $K_{\rm fudge}=1.0 \pm 0.0$.
70   Note that if we were to subtract off from region $D'$
71 < the {\color{red} $xx$} DY events estimated from
72 < Table~\ref{tab:ABCD-DYptll}, the background
73 < prediction would change to $N_D=xx$.
71 > the {\color{red} 0.4 $\pm$ 0.4} DY events estimated from
72 > Section~\ref{sec:othBG}, the background
73 > prediction would change to $N_D=0.9 \pm xx$ events.
74 > {\color{red} When we do this with a real
75 > $K_{\rm fudge}$, the fudge factor will be different
76 > after the DY subtraction.}
77  
78   As a cross-check, we use the $P_T(\ell \ell)$
79   method to also predict the number of events in the
80   control region $120<{\rm SumJetPt}<300$ GeV and
81   \met/$\sqrt{\rm SumJetPt} > 8.5$.  We predict
82   $5.6^{+x}_{-y}$ events and we observe 4.
83 < {\color{red} Note: when we do this more carefully
84 < we will need to use a different $K$ and a different $K_{fudge}$>}
83 > The results of the $P_T(\ell\ell)$ method are
84 > summarized in Figure~\ref{fig:victory}.
85  
86 + \begin{figure}[hbt]
87 + \begin{center}
88 + \includegraphics[width=0.48\linewidth]{victory_control.png}
89 + \includegraphics[width=0.48\linewidth]{victory_sig.png}
90 + \caption{\label{fig:victory}\protect Distributions of
91 + tcMet/$\sqrt{\rm SumJetPt}$ for the control and signal region.
92 + We show the oberved distributions in both Monte Carlo and data.
93 + We also show the distributions predicted from
94 + tcMet/$\sqrt{P_T(\ell\ell)}$ in both MC and data.}
95 + \end{center}
96 + \end{figure}
97 +
98 +
99 + \subsection{Summary of results}
100   To summarize: we see no evidence for an anomalous
101   rate of opposite sign isolated dilepton events
102   at high \met and high SumJetPt.  The extraction of

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