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Revision 1.5 by benhoob, Mon Nov 8 11:09:49 2010 UTC vs.
Revision 1.6 by benhoob, Mon Nov 8 13:10:39 2010 UTC

# Line 60 | Line 60 | Section~\ref{sec:othBG} to be the same a
60   $\met/\sqrt{\rm SumJetPt}$ requirement
61   replaced by a $P_T(\ell\ell)/\sqrt{\rm SumJetPt}$ requirement
62   is $N_{D'}=1$.  Thus the BG prediction is
63 < $N_D = K \cdot N_{D'} = 1.5$
64 < where $K=1.5 \pm xx$ as derived in Sec.~\ref{sec:victory}.
63 > $N_D = K \cdot K_C \cdot N_{D'} = 1.5$
64 > where $K=1.5 \pm xx$ as derived in Sec.~\ref{sec:victory} and
65 > $K_C = 1$.
66   Note that if we were to subtract off from region $D'$
67   the {\color{red} 0.4 $\pm$ 0.4} DY events estimated from
68   Section~\ref{sec:othBG}, the background

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